Question

a man sold a bike at the profit of 20% if selling price is rupees 43000 find the cost price of the bike​

Answer 1

Answer:

CONCEPT OF FOUR FUNDAMENTAL OPERATIONS , UNOTARY METHOD , PERCENTAGE , SELLING PRICE AND COST PRICE , FRACTIONS , SIMPLIFICATION.

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Answer 2

Solution:-

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ANSWER:-

• Cost price of the bike is Rs 35,833.33.

GIVEN:-

• Selling price of the bike = Rs 43,000
• Gain% of the man on selling the bike = 20%

TO FIND:-

• The cost price of the bike = ?

FORMULA:-

$\to\sf{CP\:when\:Profit\%\:is\:given=\dfrac{SP\times100}{100+Profit}}$

SOLVING BY APPLYING THE FORMULA:-

• Cost price of the bike = $\to\sf{CP\:when\:Profit\:\:is\:given=\dfrac{SP\times100}{100+Profit}}$
• Cost price of the bike = $\sf{CP \: when \: Profit\% \: is \: given = \dfrac{43000\times 100}{100 + 20}}$
• Cost price of the bike = $\sf{CP=\dfrac{430000{\not{0}}}{12{\not{0}}}}$
• Cost price = $\sf{CP=\dfrac{430000}{12}}$
• Cost price = $\sf{CP=\dfrac{430000}{12}}=35,833.33$

So, the cost price of the bike is Rs 35,833.33.

${\underline{\boxed{\large{\pink{\mathscr{\:All\:Formulae\:of\:Profit\:And\:Loss\:}}}}}}$

1. Profit = (SP > CP) = SP - CP
2. Loss = (CP > SP) = CP - SP
3. Profit% = (Profit × 100 / CP)%
4. Loss% = (Loss × 100 / CP)%
5. SP when Profit Percent is given = (100 + Profit % / 100)× CP
6. CP when Profit Percent is given = (SP × 100 / 100 + Profit %)
7. SP when Loss Percent is given = (100 - Loss / 100)× CP
8. CP when Loss Percent is given = (SP × 100 / 100 - Loss)

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