Question

a man sold an article at a profit of 10% he had he bought it at 20% less and sold it for rupees 10 on the profit of 40% the cost price of the article. {the answer is 25% loss}​

Answer 1

Step-by-step explanation:

Let the cost price of the article be Rs. x

Case 1:-

Profit = 10%

→ SP = $\rm \dfrac{100 + Profit\%}{100}\times CP$

→ SP = $\rm \dfrac{100 + 10}{100}\times x$

→ SP = $\rm \dfrac{110x}{100}$

Case 2:-

If cost price is 20% less

New CP = x - 20% = $\rm \dfrac{80x}{100}$

He got a profit of 40%

New SP = $\rm \dfrac{100 + Profit\%}{100} \times New \: CP$

New SP = $\rm \dfrac{100 + 40}{100} \times \dfrac{80x}{100}$

→ New SP = $\rm \dfrac{140}{100} \times \dfrac{80x}{100}$

→ New SP = $\rm {112x}{100}$

Given, if he bought at 20% less and sold it for Rs.10 more, he would have stilled gained 40%

So,

→ $\rm New \: SP - SP = 10$

→ $\rm \dfrac{112x}{100} - \dfrac{110x}{100} = 10$

→ $\rm \dfrac{112x - 110x}{100} = 10$

→ $\rm \dfrac{2x}{100} = 10$

→ $\rm x = 100 \times \dfrac{10}{2}$

→ $\rm x = 500$

∴ Cost price of the article = Rs. 500

Answer 2

A man sold an article at a profit of 10%. Had he bought it at 20% less and sold it for protiy of 10 more, he would have earned a profit of 40%. Find the cost price of the article.