Question

a man sold an article at a profit of 10% .if he had charged rs 45 more his profit percentage would have been 25% what is the cost price

Answer 1

 Profit%= 10%

SP= CP+ (10/100)*CP = 11CP/10.

 Now if he had sold it for RS.45 more, profit% given is 25%.

SP+45= CP + (25/100)*CP

SP + 45= 5CP/4

Substitute SP = 11 CP/10 in the above equation.

You get CP = RS. 300

Answer 2

Answer:

Cost Price of the Article is Rs. 300

Step-by-step explanation:

Given:

A man sold an article at 10% profit

If he sell the article for Rs. 45 more then the profit % is 25%

To find: The cost price of the article.

Let the Cost Price of the article = x

So, $Selling\:Price=x+\frac{10}{100}\times x=x+\frac{x}{10}=\frac{11x}{10}$

New SP = 11x/10 + 45

According to the Question,

$25=\frac{\frac{11x}{10}+45-x}{x}\times100$

$\frac{\frac{11x}{10}+45-x}{x}=\frac{1}{4}$

$\frac{11x}{10}+45-x=\frac{x}{4}$

$\frac{11x}{10}-x-\frac{x}{4}=-45$

$\frac{22x}{20}-\frac{20x}{20}-\frac{5x}{20}=-45$

$\frac{22x-20x-5x}{20}=-45$

$\frac{-3x}{20}=-45$

$x=-45\times\frac{20}{-3}$

$x=300$

Therefore, Cost Price of the Article is Rs. 300