Question

A man sold his bicycle for ₹405 losing one-tenth of its cost price. Find:

(i) its cost price; (ii) the loss percent.
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Answer 1

Step-by-step explanation:

1) Let the cost price =x

ATQ,x- x/10 = 405

or, 10x -x = 4050

or, 9x = 4050

x= 450

cost price is 450

2) loss = 45×100 / 450 =10%

Answer 2

Answer:

i)  Cost price =450 rupees, ii) Loss percent =10%

Step-by-step explanation:

According to the information provided in the question  it is given as

Selling price =Rs 450

Losing  1/10 of C P

We need to find the

i) Its cost price

ii) The loss price

Loss % = $\frac{loss}{CP} \times 100$

            =$\frac{1/10\times CP}{CP}\times 100$

Hence C P cancelled  we get

$\frac{1}{10}\times 100$

Solving to its lowest term we get

10 %  ( As 10 and 100 are divisible by 10)

According to the formula

Sp=C P -Loss

Let us assume x= cost price = C P

putting the value we get answer

$405 =x-\frac{x}{10}$

$\frac{10x -x}{10} =405$

$\frac{9x}{10} =405$

$x=405\times \frac{10}{9}$

$x =\frac{4050}{9}$

$x= 450$

As x is nothing but the C P it is equal to = 450