Question

A man sold the computer for ` 51000 at a loss of 20%. What was the cost price of the computer?

Answer 1

Answer:

the cost price of the computer =  RS. 61200

Step-by-step explanation:

Selling price = 51000

loss( percentage) = 20%

loss (in rupees) = 51000 x 20/100 = RS. 10200

cost price =   selling price + loss price

= 51000 + 10200

=  RS. 61200

hope it helps

pls mark as brainliest

Answer 2

Answer:

Rs. 63,750

Step-by-step explanation:

loss = CP - SP

Loss % = (loss/CP × 100) %

20 = [(CP - SP)/ CP × 100]

20 = [(CP - 51,000)/CP] ×100

20/100 = [(CP - 51,000)/CP]

1/5 = (CP - 51,000)/CP

1/5 CP = CP - 51,000

51,000 = CP - 1/5 CP

51,000 = 0.8 CP

51000/0.8 = CP

Rs. 63,750 = CP