Question

A man sold two articles for RS.4560 each on selling first he gains 20% and on the other he loss 30%. What is overall profit or loss percent in this transaction.

Answer 1

He Gains Profit of Rs 912 on selling first and after Selling Second He Loss Proit of Rs 1368.
Overall He Loss 31.92% And Gains 36.48%

Answer 2

Given :

The selling price of each two article = Rs 4560

The gain% on first article = 20%

The loss% on other article = 30%

To Find :

The overall profit or loss percent in this transaction

Solution :

Let The selling price of article at 20% gain = $s.p_1$

Let The cost price of article at 20% gain = $c.p_1$

Let The selling price of article at 30% loss = $s.p_2$

Let The cost price of article at 30% loss = $c.p_2$

Gain% = $\dfrac{s.p-c.p}{c.p}$

So,  20% = $\dfrac{s.p_1-c.p_1}{c.p_1}$

Or,  $\dfrac{120}{100}$  = $\dfrac{s.p_1}{c.p_1}$

Or,  $\dfrac{120}{100}$  = $\dfrac{4560}{c.p_1}$

∴    $c.p_1$  = Rs 3800

Again

Loss% = $\dfrac{c.p-s.p}{c.p}$

So,  30% = $\dfrac{c.p_1-s.p_1}{c.p_1}$

Or,  $\dfrac{70}{100}$  = $\dfrac{s.p_1}{c.p_1}$

Or,  $\dfrac{70}{100}$  = $\dfrac{4560}{c.p_2}$

∴    $c.p_2$  = Rs 6514

Now,

Total cost price of two articles = $c.p_1$ + $c.p_2$

Or,   C.P = Rs 3800 + Rs 6514

∴     C.P = Rs 10314

i.e Total cost price of two articles = C.P = Rs 10314

∵  Selling price of each article = Rs 4560

So, Total Selling price of two articles =  S.P = Rs 4560 + Rs 4560 = Rs 9120

Again

As cost price is more than selling price,  so there is a loss in overall

Thus , Loss% = $\dfrac{C.P-S.P}{C.P}$

Or,     Loss% = $\dfrac{Rs 10314-Rs 9120}{Rs 10314}$

Or,     Loss% = $\dfrac{R 1194{Rs 10314}$

∴        Loss% = 11.57

Hence, The overall loss% in this transaction is 11.57%   Answer