Math, asked by molicule713, 11 months ago

A man sold two painting at 924 each one painting has gained 20% and one other painting has lost 20% how much do he gain to loss in the

Answers

Answered by Anonymous
79
Solutions :-

Given :
A man sold two painting at 924 each.


Find the cost price one painting at 20% gain :-

C.P = (S.P × 100)/(100 + gain)
= (924 × 100)/(100 + 20)
= 92400/120
= 770


Find the cost of other painting at 20% loss :-

C.P = (S.P × 100)/(100 - loss)
= (924 × 100)/(100 - 20)
= 92400/80
= 1155


Now,
Total cost price of two painting = Rs (770 + 1155) = Rs 1925

Total Selling price of two painting = Rs (924 + 924) = Rs 1848


Cost Price is greater than the Selling price. Therefore, loss.

Loss = C.P - S.P
= Rs (1925 - 1848)
= Rs 77


Hence,
He loss Rs 77 in whole transaction.

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Anonymous: thanks alot sis, :)
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Answered by Anonymous
83
Question: A man sold two paintings at 924 each. On one painting he has gained 20% and on the other painting he has lose 20%. How much do he gain or lose in the transaction?
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Anwer:

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A man sold two paintings at the at Rs 924 per painting.

Gain %=20%

Loss %=20%

Now we will find the cost price of the both the paintings respectively.
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So the cost price of the first painting is

c.p =( \frac{s.p \times 100}{100 + gain \: on \: the \: painting} ) \\ c.p = ( \frac{924 \times 100}{100 + 20} ) \\ c.p = \frac{100}{120} \times 924 \\ c.p = Rs \: 770 \\
Now we have calculated the c. p of the painting with gain.
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So,now we will calculate the c.p of the painting with loss.

So,
C. P with 20% loss

c.p = ( \frac{s.p \times 100}{100 - 20} ) \\ c.p = \frac{924 \times 100}{100 - 20} \\ c.p = \frac{100}{80} \times 924 \\ c.p = Rs \: 1155
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Now with the Cost price of both the paintings we will find the total cost price of both the paintings.

So,

total \: cost \: price \: = cost \: price \: of \: first \: painting + cost \: price \: of \: second \: painting \\ total \: cost \: price = 770 + 1155 \\ total \: cost \: price = Rs \: 1925 \\
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Now calculate the selling price of the both the paintings respectively.

So selling price,

total \: selling \: price = selling \: \: price \: \: of \: both \: the \: paintings \times 2 \\ \\ total \: sellng \: price = 924 \times 2 \\ total \: selling \: price = r<br />Rs \: 1848
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Now to find the gain or loss in the transaction:

So, as the cost price is more than the selling price the transaction was a loss for the dealer.

total \: Loss \: in \: the \: transaction = Cost \: price - selling \: price \\ total \: Loss = 1925 - 1848 \\ total \: Loss = Rs \: 77
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So the loss in the transaction =Rs 77

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nethranithu: Wow great bro❣️❣️☺️
Anonymous: What an explanation sir ji.. wow sauru ..✌❤❤
stylishtamilachee: Great answer bro ☺❤
nethranithu: gr8 bro
AdorableAstronaut: ...
Anonymous: =_=
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