Math, asked by maleeha9956, 1 year ago

A man sold two tv sets for 4800 each.Gaining 20% on one and losing 20% on the other set.Find his net gain or loss

Answers

Answered by Anonymous
2
Solutions :-


Given :

A man sold two TV for 4800 each.


Find the cost price of one TV at gain of 20% :-

C.P = (S.P × 100)/(100 + gain)
= (4800 × 100)/(100 + 20)
= 480000/120
= 4000

Find the cost price of other TV at loss of 20% :-

C.P = (S.P × 100)/(100 - loss)
= (4800 × 100)/(100 - 20)
= 480000/80
= 6000


Now, we have

Selling price of two TV = Rs (4800 + 4800) = Rs 9600
Cost Price of two TV = Rs (4000 + 6000) = Rs 10000


Cost Price is greater than the selling price. Therefore, Loss.


Loss = C.P - S.P
= Rs (10000 - 9600)
= 400

Loss % = (loss × 100)/C.P %
= (400 × 100)/10000 %
= 40000/10000 %
= 4 %


Hence,
Loss = Rs 400
Loss percent = 4%
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