Question

A man speed is 12 km/h how many distance he covered in 2 hours 45 min

Answer 1

GIVEN:

• Speed of the man = 12 km/hr
• Time taken by the man = 2 hr 45 min.

TO FIND:

• What is the distance covered by the man ?

SOLUTION:

Convert the time taken by the man in hours.

• $\sf{ 1 \: hr = 60 \: minutes}$
• $\sf{ 2 \: hr = 2 + \dfrac{45}{60}}$
• $\sf{ 2 + \dfrac{3}{4}}$
• $\sf{ \dfrac{8 +3}{4}}$
• $\bf{ Time = \dfrac{11}{4} \: hr }$

Let the distance covered by the man be 'D' km

We know that the formula for finding the distance covered is :-

$\large{\boxed{\bf{\star \: DISTANCE = SPEED \times TIME \: \star}}}$

According to question:-

On putting the given values in the formula, we get

$\sf{\longmapsto D = 12 \times \dfrac{11}{4} }$

$\sf{\longmapsto D = \cancel\dfrac{132}{4} }$

$\bf{\longmapsto D = 33 \: km}$

❝ Hence, the distance covered by the man is 33 km ❞

______________________

Answer 2

UR QUESTION:-

A man speed is 12 km/h how many distance he covered in 2 hours 45 min

UR ANSWER✓

$\Large\bold\purple{given,}$

$\sf\dashrightarrow speed = 12 \dfrac{km}{hr}$

$\sf\dashrightarrow time taken(T)=2 hours\:45min$

$\Large\underline\bold{TO\:FIND}$

$\sf\large\dashrightarrow distance\:covered\:in\:2\:hours\:and\:45\:min$

$\Large\underline\bold{conversion,}$

$\sf\therefore converting\:the\:time\:taken\:by\:the\:man\:in\:hours$

$\sf\therefore{ 1\: hr = 60 \: minutes}$

$\sf\implies{ 2\: hr = 2 + \dfrac{45}{60}}$

$\sf\implies{ 2+ \dfrac{3}{4}}$

$\sf\implies{ \dfrac{8 +3}{4}}$

$\sf\:implies{ Time = \dfrac{11}{4} \: hr }$

$\Large\underline\bold{solution}$

A.T.Q......i.e.,.... according to the question,

$\sf\implies let\:time\:be\:denoted\:as\:T$

$\sf\implies let\:distance\:be\:denoted\:as\:D$

$\Large\underline\bold{formula,}$

$\sf\therefore distance\:covered\:= speed \times time$

now,

$\sf{\therefore D = 12 \times \dfrac{11}{4} }$

$\sf{\therefore D = \dfrac{132}{4} }$

$\sf{\therefore D = \cancel \dfrac{132}{4} }$

$\sf{\therefore D = 33 \: km}$

$\large{\boxed{\sf{distance=33km}}}$

$\sf\therefore distance\:covered\:by\:the\:man\:in\:2hours\:45\:min\:is\:33km$

________________________________

ADDITIONAL INFORMATION,

Formally the information distance ,

${\displaystyle ID(x,y)}ID(x,y)$between ${\displaystyle x}$ and ${\displaystyle y}$ is defined by,

${\displaystyle ID(x,y)=\min\{|p|:p(x)=y\;\&\;p(y)=x\},}$

$ID(x,y)=\min\{|p|:p(x)=y\;\&\;p(y)=x\},$

with

${\displaystyle p}$

a finite binary program for the fixed universal computer with as inputs finite binary strings

${\displaystyle x,y}$.

${\displaystyle ID(x,y)=E(x,y)+O(\log \cdot \max\{K(x\mid y),K(y\mid x)\})}ID(x,y)=E(x,y)+O(\log \cdot \max\{K(x\mid y),K(y\mid x)\})$with

${\displaystyle E(x,y)=\max\{K(x\mid y),K(y\mid x)\},}E(x,y)=\max\{K(x\mid y),K(y\mid x)\},$

where,

${\displaystyle K(\cdot \mid \cdot )}K(\cdot \mid \cdot )$ is the Kolmogorov complexity of the prefix type.

This ${\displaystyle E(x,y)}E(x,y) is\: the \:important\: quantity.$