Question

A man stand between two parallel clips fires a gun . He hears the first echo after 1.5 sec and next after 2.5 sec . What is the distance between the clips and when does he hear third echo..?

Answer 1

v=2d/v d1+d2=d V of sound in air is 330m/s t1=1.5sec t2=2.5sec d1= v x t1/2 330*1.5/2=247.5m now d2= v x t2/2 330*2.5/2=412.5m Now as we know d1 + d2= d Hence =247.5 + 412.5= 660m(ans)