Question

A man standing between 2 parallel eliffs
fires a gun. He hearns two echos one
after 3 seconds and other after 5 seconds.
The separation between the two cliffs is
1360 m, what is the speed of sound?​

Answer 1

Part 1: using the formula 2d=vt, where v= the speed of sound, 330m/s, t= time taken and d = distance, plug in the given values into the formula and you get d= 330m. Part 1 is done!

Part 2 : do the same for this, see the above. ( you'll get d= 660m)

So, 330m is the distance from the shooter and the cliff, which reflected the sound wave to produce the 2s echo, while 660m is the distance from the shooter and the other cliff, which reflected the sound wave to produce the 4s echo. The distance between the cliffs is the sum of the distances which you found.

Answer 2

Hi✌️✌️

✍...

Part 1: using the formula 2d=vt, where v= the speed of sound, 330m/s, t= time taken and d = distance, plug in the given values into the formula and you get d= 330m. Part 1 is done!

Part 2 : do the same for this, see the above. ( you'll get d= 660m)

So, 330m is the distance from the shooter and the cliff, which reflected the sound wave to produce the 2s echo, while 660m is the distance from the shooter and the other cliff, which reflected the sound wave to produce the 4s echo. The distance between the cliffs is the sum of the distances which you found.

I hope it will help you ❣️❣️