Question

A man standing between two cliffs produces a sound and hears two successive echoes at intervals of 3s and 4s respectively .Calculate the distance between the two cliffs.The speed of sound in air is 330m/s?

Answer 1

Answer:

If velocity of sound is 330m/s, then what is the distance between 2 cliffs ... We want to find d . d=d1+d2. So we need to find d1 and d2. Using s=v⋅t (s is displacement, v is velocity, t is time):. 2d1=330×3. For the echo to be heard, the sound needs to get to the cliff ( d1 ) ... We can do the same for the second cliff.

Explanation: