Physics, asked by sunithasivakumar915, 11 months ago

A man standing between two parallel cliff fires a rifle. he hears one echo after1.5s and another 2.5s if the velocity of the sound is 340m/s what is the distance between the cliff​

Answers

Answered by Anonymous
5

first echo =1.5

second echo=2.5

=1.5*2.5=375

Now distance travel by twice cliffs =375*340=127500m

now, 340/127500=43350000

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