Question

a Man Standing between two vertical walls 680m apart.he claps his hands and hears two distant echoes 0.9 seconds and 1.1 second respectively .what is the speed of sound in the air​

Answer 1

Answer:

HELLO BUDDY ❤️ HERE IS UR ANSWER

GIVEN:-

time of first echo t1=0.9s

time of second echo t2=1.1s

distance between man and wall ,d=680 m

TO FIND:-speed of sound in air,c=?

SOLUTION:-

speed of sound in air,c=2d/t

c=2d/t1+t2

c=2×680/(0.9+1.1)

=2×680/2

speed of sound in air,c=680m|s

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Answer 2

Answer:

hello friend✌️

answers is in the attachment

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