A man standing in a valley between two parallel mountains fires a gun and hears echo at an interval of 2 seconds and 3.5 seconds.what is (a)the distancebetween two mountains (b) the location of the man with respect to the mountain?
Answers
Answered by
11
Answer : Speed of sound = 340 m/sec .
Let the distance b/w nearest clif and man = x m
and the distance b/w distant clif and man = y m
Distance b/w two clif = ( x + y ) m
Total distance covered by sound to produce first echo
= 2x m and time = 2 sec
=> 2y = 340 x 2
=> x =(340 x 2)/2 = 340 m
Total distance covered by sound to produce 2nd echo = 2y m and time = 3.5 sec
=> 2y = 340 x x 3.5
=> y = (340 x 3.5)/2 = 595 m
So, Distance b/w two clif = ( 340 + 595) = 935 m
Let the distance b/w nearest clif and man = x m
and the distance b/w distant clif and man = y m
Distance b/w two clif = ( x + y ) m
Total distance covered by sound to produce first echo
= 2x m and time = 2 sec
=> 2y = 340 x 2
=> x =(340 x 2)/2 = 340 m
Total distance covered by sound to produce 2nd echo = 2y m and time = 3.5 sec
=> 2y = 340 x x 3.5
=> y = (340 x 3.5)/2 = 595 m
So, Distance b/w two clif = ( 340 + 595) = 935 m
Similar questions