Question

An aircraft is flying with uniform speed at a height 3400m above the ground if the angle subtended at observation point by the aircraft positions 10 sec apart is 30 what is the speed

Answer 1

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Aircraft is at 3400 m hight.

it is substendin 30 deg it means it is making 15 deg angle from one side of head to another side.

now distance moved by aircraft is 2* 3400*tan15 = 1822.054mm

speed = distance/time
=1822.055/10 m/s
182.2 m/s

Answer 2

Answer:

tanθ=opp/adj (∴adj = x)

tan30 = 3400/adj m

adj = 3400/ tan30 m (∴tan30=1/√3)

adj = 3400/1/√3 m

adj = 5889 m

Total time taken t = 10.0 s

speed of aircraft v = adj / t =5889/10 m/s

∴v=588.9 m/s