Question

a man standing near a water body observe a rock immersed inside the water can he see the rock in its actual position explain with the help of a diagram
plz I also need diagram also ​

Answer 1

To explain:

A man standing near a water body observe a rock immersed inside the water. Can he see the rock in its actual position ?

Solution:

Whether the man sees the stone in its actual position or at a raised (apparent) position , it simply depends upon his viewing.

When the man is looking at the rock from vertically up:

Applying Snell's Law:

$\therefore \: \mu \sin(i) = 1 \times \sin(r)$

$\implies \: \mu \sin( {0}^{ \circ} ) = 1 \times \sin(r)$

$\implies \: \mu \times 0 = 1 \times \sin(r)$

$\implies \: \sin(r) = 0$

$\implies \: r = {0}^{ \circ}$

So, rays from the rock don't undergo any deviation at the water-air interface. Hence, the man will see the rock at its actual position.

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When the man looks at the rock from a different angle:

• Refer to diagram.

• The light rays originating from the rock will deviate away from the normal , while getting refracted at the water-air interface.

• When the refracted ray is extended backwards, it produces an image of the rock at a higher position.

• The observer perceives this image as the original object , and the man watches the rock at a higher apparent depth.