a man standing on a platform 225 M long notices that is train travelling at uniform speed passes him in 6 seconds and passes by the platform in 21 seconds find the length of the train and the speed of the train
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Length of train = L
length of platform= 225m
time taken by train to cross the man = 6s
distance travelled by train to cross the man = L
time taken to cross platform= 21s
distance travelled by train to cross the platform= (L+225)m
So, in order to travel {(L+225) - (L)}m, train takes (21 - 6) second
Or train travels 225m in 15 second
speed of train = 225/15 = 15 m/s
Length of train = speed of train × time taken to cross the man = 15 × 6 = 90m
length of platform= 225m
time taken by train to cross the man = 6s
distance travelled by train to cross the man = L
time taken to cross platform= 21s
distance travelled by train to cross the platform= (L+225)m
So, in order to travel {(L+225) - (L)}m, train takes (21 - 6) second
Or train travels 225m in 15 second
speed of train = 225/15 = 15 m/s
Length of train = speed of train × time taken to cross the man = 15 × 6 = 90m
joy28:
where is the speed of the train
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