A man started a journey at 09:30 h and arrived at his destination, in the same time zone, at 13:30 h on the same day. If is average speed was 30 km/h, then the distance, in km/h, for the journey was?
Answers
Answered by
1
Answer:
7200km is the answer
Step-by-step explanation:
difference between time =4 hours
4×60×30
=240×30
=7200 km
Answered by
1
Hey mate here is your answer.//
Step-by-step explanation:
Initial destination of the man,(started)
=9:30 am.
Final destination of the man,(ended)
=13:30 or 1:30 pm.
Average speed of the man
=30 km/h.
So the total distance covered by the man,
= to the product of average speed and the total time taken.
=13:30-9:30
=4 hours is the time
total ditance= 30 km/h × 4 hours
= 120 km.
So, the distance coverd by the man in his total journey is 120km.
Hope it helps you.//✔✔✔
Please do mark me as Brainliest.//
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