Math, asked by azeealeem, 9 months ago

A man started a journey at 09:30 h and arrived at his destination, in the same time zone, at 13:30 h on the same day. If is average speed was 30 km/h, then the distance, in km/h, for the journey was?

Answers

Answered by avnibhasin08
1

Answer:

7200km is the answer

Step-by-step explanation:

difference between time =4 hours

4×60×30

=240×30

=7200 km

Answered by miliganatra1291
1

Hey mate here is your answer.//

Step-by-step explanation:

Initial destination of the man,(started)

=9:30 am.

Final destination of the man,(ended)

=13:30 or 1:30 pm.

Average speed of the man

=30 km/h.

So the total distance covered by the man,

= to the product of  average speed and the total time taken.

=13:30-9:30

=4 hours is the time

total ditance= 30 km/h  × 4 hours

= 120 km.

So, the distance coverd by the man in his total journey is 120km.

Hope it helps you.//✔✔✔

Please do mark me as Brainliest.//

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