Question

A man starts from (20 m, 0) moves along +x direction such that his position from his point of start is S = 2t² + 5 t. His position from the origin at t = 2 sec is​

Answer 1

Refer to the attachment

Answer 2

Given info : A man starts from (20, 0) moves along + x direction such that his position from his point of start is S = 2t² + 5t.

To find : his position from the origin at t = 2 sec.

solution : initial position of the man, S₀ = 20 m

now distance covered by the man at t = 2sec, S₁ = 2(2)² + 5(2) = 18 m

∴  the position of the man from the origin at (t = 2 sec ) = S₀ + S₁

                                                                                       = 20 m + 18 m = 38m

therefore the position of the man from the origin at t = 2 sec is (38m, 0).

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