Question

a man starts from a point and goes 10 metre towards east. then he turns towards north goes 24 and finally stops find the distance between the starting point and endpoint​

Answer 1

Answer:

A man goes 10m towards east so let the distance between man and point be AB=10m

then he move 24m towards north let that be BC=24m

so it will form a shape like right angle triangle ABC in which AB is 10m BC is 24 so for the distance between man and the starting point will be AC which will be the hypotenuse

so by pythagoras theorem

AC square =AB square +BC square

=

${x }^{2} = 24 {}^{2} + 10 { }^{2}$

$x {}^{2} = 100 + 576$

${x }^{2} = 676$

$x = \sqrt{676}$

$x = \sqrt{26 \times 26}$

$x = 26$

so the distance between starting point and ending point of a man is 26m