Question

A man starts from his house , he moves 5 m due west then turns and moves 12 m due north. How far is he from his house ?​

Answer 1

$\huge{ \boxed{ \fcolorbox{cyan}{pink}{Answer}}}$

$\; \; \;$

• By applying Pythagoras theorem,

$\bold \orange { : \longmapsto \: {x}^{2} = {12}^{2} + {5}^{2} }$

$\bold \purple { : \longmapsto \: {x}^{2} = 144 + 25}$

$\bold \orange { : \longmapsto \: {x}^{2} = 169}$

$\bold \purple { : \longmapsto \: x = 13}$

$\; \; \;$

$\boxed{ \fcolorbox{cyan}{black}{ \boxed{\bold \pink{ \boxed{ \fcolorbox{cyan}{orange}{ \boxed{\bold \purple{ He \; is \; 13 \; meters \; far. }}}}}}}}$

Answer 2

Answer:

$hy { }^{2} = b { }^{2} + \: \: p {}^{2} \: \\ hy {}^{2} = 5 {}^{2} + 12 { }^{2} \\ hy { }^{2} = 25 + 144 \\ hy = \sqrt{169} \\ hy = 13$