Question

A man starts from the village temple in the direction of East.After walking 8 miles he turns left.After walking another 3 miles he again turns to left.Now after walking four miles,how far away he would be from the temple?​

Answer 1

5 miles by taking right angle triangle

side A -8-4=4

side B 3 miles

will give 5 miles

Answer 2

This will be ur diagram.

Let,

The distance from the temple to the east 8 miles be AB.

The distance left from AB i.e.

to north 4 miles be BC

AB is perpendicular to BC

Thus,

Triangle ABC is a right angled triangle with angle ABC = 90

Distance between temple and the persons present position will be AC

AC is the hypotenuse of triangle ABC

By Pythagoras Theorem,

AC2 = AB2 + BC2

AC2 = (8*8) + (4*4)

AC2 = 64 + 16

AC2 = 80

AC =

$\sqrt{16 \times 5 } = 4 \sqrt{5}$

Answer :

The distance between temple and actual or present position of the person will be 4(underroot)5

Hope it helps you out

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