Math, asked by asmamomin925, 5 months ago

A man starts his job with a certain monthly
salary and a fixed increment every year. If
his salary will be * 11,000 after 2 years and
14,000 after 4 years of his service, what
was his starting salary and what is the
annual increment?​

Answers

Answered by pp8601487
5

Answer:

Let starting salary = x

Let starting salary = xIncrement every year = y

Let starting salary = xIncrement every year = yx +2y = 11,000 ....... eq(1)

Let starting salary = xIncrement every year = yx +2y = 11,000 ....... eq(1)x + 4y = 14,000 ......eq(2)

Let starting salary = xIncrement every year = yx +2y = 11,000 ....... eq(1)x + 4y = 14,000 ......eq(2)Substract eq(1) from eq(2)

Let starting salary = xIncrement every year = yx +2y = 11,000 ....... eq(1)x + 4y = 14,000 ......eq(2)Substract eq(1) from eq(2)2y = 3,000

Let starting salary = xIncrement every year = yx +2y = 11,000 ....... eq(1)x + 4y = 14,000 ......eq(2)Substract eq(1) from eq(2)2y = 3,000y = 1500

Let starting salary = xIncrement every year = yx +2y = 11,000 ....... eq(1)x + 4y = 14,000 ......eq(2)Substract eq(1) from eq(2)2y = 3,000y = 1500 Substitute y= 1500 in eq(1), we get x = 11,000 − 3,000

Let starting salary = xIncrement every year = yx +2y = 11,000 ....... eq(1)x + 4y = 14,000 ......eq(2)Substract eq(1) from eq(2)2y = 3,000y = 1500 Substitute y= 1500 in eq(1), we get x = 11,000 − 3,000x = 8,000

Let starting salary = xIncrement every year = yx +2y = 11,000 ....... eq(1)x + 4y = 14,000 ......eq(2)Substract eq(1) from eq(2)2y = 3,000y = 1500 Substitute y= 1500 in eq(1), we get x = 11,000 − 3,000x = 8,000starting salary = 8,000

Let starting salary = xIncrement every year = yx +2y = 11,000 ....... eq(1)x + 4y = 14,000 ......eq(2)Substract eq(1) from eq(2)2y = 3,000y = 1500 Substitute y= 1500 in eq(1), we get x = 11,000 − 3,000x = 8,000starting salary = 8,000 Increment = 1500

Answered by ishanikapoor217
3

Answer:

Answer:

Step-by-step explanation:

Given,

A man starts his job with a certain monthly salary and a fixed increment every year.

Salary will be Rs. 11000  after 2  years and Rs. 14000 after 4 years of his service.

To Find,

Starting salary and Annual increment.

Solution,

Let starting salary of a man be Rs. x

And the fixed annual increment be Rs. y.

Now, According to the question,

⇒ x + 2y = 11000 _(i)

⇒ x + 4y = 14000 _(ii)

Now, On subtracting (i) from (ii), we get  

⇒ 2y = 3000

⇒ y = 3000/2

⇒ y = 1500

Hence, the fixed annual increment of a man is Rs. 1500.

Now, On substituting y's value in eq (i), we get

⇒ x + 2y = 11000

⇒ x + 2 × 1500 = 11000

⇒ x + 3000 = 11000

⇒ x = 11000 - 3000

⇒ x = 8000

Hence, the starting salary of a man is Rs. 8000.

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