Question

A man starts travelling 5m towards east turns towards south and walks 4m . Find the distance and displacement

Answer 1

distance is the length of the path travelled
displacement is the shortest path travelled from initial to final point

Answer 2

Answer: The distance is 9 m and displacement is 6.4 m.

Explanation:

Given that,

A man starts travelling 5 m towards east turns towards south and walks 4 m.

Let A and B is the initial and final position.

Therefore, The displacement between A and B

Using Pythagoras theorem

$AC = \sqrt{(AB)^{2}+(BC)^2}$

$AC = \sqrt{(5)^{2}+(4)^2}$

$AC = \sqrt{25+16}$

$AC = 6.4\ m$

The distance is

$d = AB+BC$

$d = 5\ m+4\ m$

$d = 9\ m$

Hence, The distance is 9 m and displacement is 6.4 m.