A man steadily goes 10 m due east and then 24 m due north. (i) Find the distance from the starting point.
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if he went 10m east and then 24m north, then a right angle triangle is formed
the distance from staring point=24^2 + 10^2 = 576 + 100 = 676 = √676 =26
so the answer is 26m
if it is helpful Pl mark it brainliest answer
the distance from staring point=24^2 + 10^2 = 576 + 100 = 676 = √676 =26
so the answer is 26m
if it is helpful Pl mark it brainliest answer
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