a man thrown ball vertical with velocity 10m/s find flights of time
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time of flight=2u/g
here u=10m/s, g=9.8m/s ^2
T=2×10/9.8
=2.04 sec
here u=10m/s, g=9.8m/s ^2
T=2×10/9.8
=2.04 sec
sadhanalajayaprakash:
Answer is right but no clear explanation. Well done
formula to find time of flight is 2u/g. i just substituted the values in the formula. no confusion.
here u= initial velocity and g= acceleration due to gravity(9.8 ms-2).
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u=10m/s a= -10m/s Time taken to reach highest point ( v=0m/s )
v = u + at
0 = 10 + (-10)t
Therefore t = 1s.
Now time taken to reach back to earth is also 1s.
Therefore time of flight = 1s + 1s = 2s
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