A man throws a ball of mass 0.5 kg vertically upward with a velocity of 25 m/s. Find : (a) the initial momentum of the ball (b) momentum of the ball at the half way mark of the maximum height (given g10 m/s2)
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Intial Momentum = Mass * Velocity
=0.5*25
12.5kgms^-1
2(a)(s)=v^2-u^2
2(10)(s)=0-(25)^2
s=31.25metres
31.25/2=15.625 distance for halfway
velocity of Ball at this distance=30.6
Momentum=30.6*0.5
15.3kgms-1
=0.5*25
12.5kgms^-1
2(a)(s)=v^2-u^2
2(10)(s)=0-(25)^2
s=31.25metres
31.25/2=15.625 distance for halfway
velocity of Ball at this distance=30.6
Momentum=30.6*0.5
15.3kgms-1
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