Physics, asked by elenajohnalackel, 4 days ago

a man throws a ball of mass 150 g to a wall with a velocity of 20m/s and it rebounces with the same velocity. Find the change in the momentum.​

Answers

Answered by rsagnik437
97

Answer :-

Change in momentum of the ball is -6 kg m/s .

Explanation :-

We have :-

→ Mass of the ball (m) = 150 g = 0.15 kg

→ Initial velocity (u) = 20 m/s

→ The ball rebounces with same velocity.

To find :-

→ Change in momentum .

________________________________

Initially the ball was moving in a certain direction. After hitting the wall, the ball rebounces in the opposite direction. So, final velocity of the ball (v) will be -20 m/s .

Initial momentum of the ball :-

= Mass × Initial velocity

= m × u

= 0.15 × 20

= 3 kg m/s

Final momentum of the ball :-

= Mass × Final velocity

= m × v

= 0.15 × (-20)

= -3 kg m/s

Change in momentum :-

= Final momentum - Initial momentum

= (-3 - 3) kg m/s

= -6 kg m/s


Ladylaurel: Great!
rsagnik437: Thankuu :)
Answered by Anonymous
48

Answer:

Question :-

  • A man throws a ball of mass 150g to a wall with a velocity of 20m/s and it rebounces with a same velocity. Find the change in the momentum.

 \sf\tt\large{\purple {\underline {\underline{⚘\;Answer:}}}}

 \sf\tt\large{\blue {\underline {\underline{⚘\;The \;change \;in \;momentum \;of \;the \;ball \;is \;-6kgm/s:}}}}

 \sf\tt\large{\red {\underline {\underline{⚘\;Given:}}}}

  • A man throws a ball of mass 150g to a wall with a velocity of 20m/s and it rebounces with a same velocity.
  • Mass of the given ball=150g=0.15kg.

 \sf\tt\large{\red {\underline {\underline{⚘\;To find:}}}}

  • Change in momentum of the given ball.

 \sf\tt\large{\red {\underline {\underline{⚘\;Solution:}}}}

  • Here,

  • First we should find the initial momentum and final momentum of the given ball then at final lets find the change in momentum of the given ball.

 \sf\tt\large{\red {\underline {\underline{⚘\;Case (i):}}}}

  • Initial momentum =mass ×given initial velocity.

  • Lets apply the values,

  • Initial momentum =0.15kg×20
  • Initial momentum =3 kg m/s.

 \sf\tt\large{\red {\underline {\underline{⚘\;Case  (ii):}}}}

  • Final momentum =mass×final velocity of ball

  • Lets apply the values we get that,

  • Final momentum =0.15kg×(-20)m/s
  • Final momentum =-3kg m/s.

 \sf\tt\large{\red {\underline {\underline{⚘\;Final \;result:}}}}

  • Change in momentum of the given ball =Final momentum- initial momentum
  • Change in momentum of the given ball = -3 - 3

  • Change in momentum of the given ball =-6kg m/s.

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