a man throws a ball of mass 150 g to a wall with a velocity of 20m/s and it rebounces with the same velocity. Find the change in the momentum.
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Answered by
97
Answer :-
Change in momentum of the ball is -6 kg m/s .
Explanation :-
We have :-
→ Mass of the ball (m) = 150 g = 0.15 kg
→ Initial velocity (u) = 20 m/s
→ The ball rebounces with same velocity.
To find :-
→ Change in momentum .
________________________________
Initially the ball was moving in a certain direction. After hitting the wall, the ball rebounces in the opposite direction. So, final velocity of the ball (v) will be -20 m/s .
Initial momentum of the ball :-
= Mass × Initial velocity
= m × u
= 0.15 × 20
= 3 kg m/s
Final momentum of the ball :-
= Mass × Final velocity
= m × v
= 0.15 × (-20)
= -3 kg m/s
Change in momentum :-
= Final momentum - Initial momentum
= (-3 - 3) kg m/s
= -6 kg m/s
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Answer:
Question :-
- A man throws a ball of mass 150g to a wall with a velocity of 20m/s and it rebounces with a same velocity. Find the change in the momentum.
- A man throws a ball of mass 150g to a wall with a velocity of 20m/s and it rebounces with a same velocity.
- Mass of the given ball=150g=0.15kg.
- Change in momentum of the given ball.
- Here,
- First we should find the initial momentum and final momentum of the given ball then at final lets find the change in momentum of the given ball.
- Initial momentum =mass ×given initial velocity.
- Lets apply the values,
- Initial momentum =0.15kg×20
- Initial momentum =3 kg m/s.
- Final momentum =mass×final velocity of ball
- Lets apply the values we get that,
- Final momentum =0.15kg×(-20)m/s
- Final momentum =-3kg m/s.
- Change in momentum of the given ball =Final momentum- initial momentum
- Change in momentum of the given ball = -3 - 3
- Change in momentum of the given ball =-6kg m/s.
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