Question

A man throws a ball vertically upwards with a velocity of 25m/s. Assuming g=10m/s2
a) find the height of the ball rises through in 2s.
b) How long will the ball take to come back to the ground?
Solve the question

Answer 1

Answer:

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Answer 2

$\huge\bold\star\red{QUESTION}\star$

A man throws a ball vertically upwards with a velocity of 25m/s. Assuming g=10m/s2

a) find the height of the ball rises through in 2s.

b) How long will the ball take to come back to the ground?

Solve the question

$\huge\bold\star\red{ANSWER}\star$

(a)

The ball is thrown upwards.∴ Acceleration due to gravity =−9.8m/s2Final velocity = 0m/sInitial velocity =25 m/sDistance =35 mTime =1.5 secTo find total distance traveled: the distance traveled by the ball in upward and downward motion will be the same. Hence, the total distance will be 35 m+35 m=70 mTo find position after 2 secUsing the formula:s=ut+21at2s=25×2+21×−9.8×(2)2s=50+(−19.6)s=30.4 m

(b)

Initial velocity of the ball final velocity =0m/sacceleration due to gravity (g)=−10m/s 2 (upward motion)By using the formula,v=u+atO=25+(−10)×t10t=25t=2.5sec.The time taken for upward journey is equal to the time taken for downward journey.Therefore, total time taken by the ball =2.5+2.5=5sec.