Physics, asked by timesfeedback, 9 months ago

A man throws a ball with a velocity of 20m/s. After what time will the ball come back to his hands? (Take g =10m/s^2)

Answers

Answered by lakshay007237
4

Answer:

Given final velocity v= 0 m/s and displacement h= 20 m; acceleration due to gravity = 10 m/ s 2

From equation of motion 

v2=u2+2gs−u2=−2(10).20u=20m/s

and time t can be determined by the formula

t=gv−u=−10−20=2s

total time = 2× time of ascend=2×2=4s

Explanation:

this is the brainly answer

Answered by EISSA123
1

Answer:

hope this helps.

Explanation:

The acceleration (in round numbers and ignoring all forces except the pull of gravity) is minus 10 m per second per second. That means the velocity changes by 10 m/s every second.

The up and down parts of the trajectory will be symmetrical.

t = 0, v = +20 m/s, a = - 10 m/s/s

t = 1s, v = +10 m/s, a = - 10 m/s/s

t = 2s, v = 0 m/s, a = - 10 m/s/s (highest point)

t = 3s, v = - 10 m/s, a = - 10 m/s/s

t = 4s, v = - 20 m/s, a = - 10 m/s/s (back at start

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