A man throws a ball with a velocity of 20m/s. After what time will the ball come back to his hands? (Take g =10m/s^2)
Answers
Answer:
Given final velocity v= 0 m/s and displacement h= 20 m; acceleration due to gravity = 10 m/ s 2
From equation of motion
v2=u2+2gs−u2=−2(10).20u=20m/s
and time t can be determined by the formula
t=gv−u=−10−20=2s
total time = 2× time of ascend=2×2=4s
Explanation:
this is the brainly answer
Answer:
hope this helps.
Explanation:
The acceleration (in round numbers and ignoring all forces except the pull of gravity) is minus 10 m per second per second. That means the velocity changes by 10 m/s every second.
The up and down parts of the trajectory will be symmetrical.
t = 0, v = +20 m/s, a = - 10 m/s/s
t = 1s, v = +10 m/s, a = - 10 m/s/s
t = 2s, v = 0 m/s, a = - 10 m/s/s (highest point)
t = 3s, v = - 10 m/s, a = - 10 m/s/s
t = 4s, v = - 20 m/s, a = - 10 m/s/s (back at start