Question

The magnetic flux through a loop varies according to the relation

 = 8t2+6t+C, where C is a constant and  in in millimeter and ‘t’ in second. What

is the magnitude of induced emf in the loop at t = 2 sec.​

Answer 1

Answer:

The magnitude of induced EMF will be 38 mV or 0.038 V

Explanation:

Ε = -dΦ/dt

Hence, after differentiating

E = -(16t+6)

Putting value of t=2sec

E = -38 mV.

Millivolt because Φ is given in "milliweber" too.