Question

a man throws balls with the same speed vertically upwards one after other at an interval of 2 sec. what should be the speed of the throw so that mare than are in the sky at any time.

Answer 1

the first has to be above the ground when the second ball is thrown from the ground

 

so the first ball has to be above from the ground for 2 seonds.

 

s=ut-1/2*gt^2        t=2  and s=0 when first ball reaches the ground

 

0= 2*u- 1/2*g*4

 

u=g m/s        take g=9.8 m/s^2

u= 9.8 m/s

 

speed has to be more than 9.8 m/s

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