A man travel 370km partly by train and partly by car if he covers 250km by train and the rest by car,he takes 4hours.But if he travel 130km by train and rest by car,he takes 18minutes more. Find the speed of the train and car.
Answers
Answer:
Let the speed of the car be C kmph
Let the speed of the train be T kmph
4 hours = 250 km / T kmph + (370 - 250) km / C kmph
4 = 250/T + 120/C -- equation 1
4 hrs 18 minutes = 130 km / T kmph + (370 - 130)km / C kmph
258/60 = 4.3 = 130 / T + 240 / C --- equation 2
Multiply equation 1 by 2 and subtract equation 2 from it.
8 - 4.3 = 500/T - 130/T + 240/C - 240/C
3.7 = 370 / T
T = 370/3.7 = 100 kmph
Substitute the value of T in equation 1 to get,
4 = 250/T + 120/C -- equation 1
4 = 250/100 + 120/C
4 - 2.5 = 120/C
C = 120/1.5 = 80 kmph
The train runs at 100 kmph and the car runs at 80 kmph
Let the speed of a train= x km/hr &
Let the speed of a train= x km/hr &the speed of a car= y km/hr
Total distance travelled= 370km
A/q
If he covers 250km by train & rest by car i.e.(370-250)= 120km
Time taken 4 hrs
If he travels 130km by train & rest by car i.e. (370-130)= 240km.
He takes 18m longer i.e.
So, total time=train time+ car time
We know that,
250u+120v= 4........(3)&
250u+120v= 4........(3)&130u+240v= 4.3......(4)
On multiplying equation (3) by 2
=) 500u+240v= 8.......(5)
On subtracting equation (4) from (5), we get
500u+240v-130u-240v= 8-4.3
=) 370u= 3.7
=) u= 3.7/370
=) u= 1/100
On putting the value of u in equation (4), we get
So, we get u= 1/100 & v= 1/80
x= 100 & y= 80
Hence, the speed of the train is 100km/hr & the speed of the car is 80km/hr.