Physics, asked by maganior, 1 year ago

a man traveled a distance of 45m in the 5th second starting from rest then the acceleration of the man Is?

Answers

Answered by Mankuthemonkey01
8
Velocity = Displacement/Time


Here Distance is the displacement since it's not given that the man returns to its initial position. Hence, Distance is displacement here.

So v = 45/5
v = 9m/s


We know that acceleration= v - u/t

V = 9
u = 0 (since it starts from rest)
t = 5


=> acceleration = 9 - 0/5
= 9/5
= 1.8 m/s²


Hope it helps dear friend ☺️✌️✌️

maganior: tq
Mankuthemonkey01: welcome
maganior: please answer other
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