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Answered by
5
HELLO DEAR,
LET THE RADIUS OF THE OUTER BOUNDARY BE (R CM)
GIVEN THAT:-
TOTAL AREA OF THE RING =346.5CM²
π (R²-14²)=346.5
![\frac{22}{7} \times ( {r}^{2} - 196) = 346.5 \\ = > 22 \times ( {r}^{2} - 196) = 2424.5 \\ = > ( {r }^{2} - 196) = 110.25 \\ = > {r}^{2} = 110.25 + 196 \\ = > {r}^{2} = 306.25 \\ = > r = 17.5 \frac{22}{7} \times ( {r}^{2} - 196) = 346.5 \\ = > 22 \times ( {r}^{2} - 196) = 2424.5 \\ = > ( {r }^{2} - 196) = 110.25 \\ = > {r}^{2} = 110.25 + 196 \\ = > {r}^{2} = 306.25 \\ = > r = 17.5](https://tex.z-dn.net/?f=+%5Cfrac%7B22%7D%7B7%7D++%5Ctimes+%28+%7Br%7D%5E%7B2%7D++-+196%29+%3D+346.5+%5C%5C++%3D++%26gt%3B+22+%5Ctimes+%28+%7Br%7D%5E%7B2%7D++-+196%29+%3D+2424.5+%5C%5C++%3D++%26gt%3B+%28+%7Br+%7D%5E%7B2%7D++-+196%29+%3D+110.25+%5C%5C++%3D++%26gt%3B++%7Br%7D%5E%7B2%7D++%3D+110.25+%2B+196+%5C%5C++%3D++%26gt%3B++%7Br%7D%5E%7B2%7D++%3D+306.25+%5C%5C++%3D++%26gt%3B+r+%3D+17.5)
I HOPE ITS HELP YOU DEAR,
THANKS
LET THE RADIUS OF THE OUTER BOUNDARY BE (R CM)
GIVEN THAT:-
TOTAL AREA OF THE RING =346.5CM²
π (R²-14²)=346.5
I HOPE ITS HELP YOU DEAR,
THANKS
rohitkumargupta:
Hey dear
Answered by
3
Radius of the inner boundary (r) = 14 cm
Area of the ring(doesn't include inner boundary area) = 364.5 cm²
Area of the inner boundary = π r²
= 3.14 × 14 × 14
= 615.44 cm²
Total area of the ring (includes areas of both boundaries) = 615.44 + 364.5
= 979.94 cm²
Radius of the outer boundary = √(979.94/3.14)
=√312.08
Radius of the outer boundary is 17.66 cm.
-WonderGirl
Area of the ring(doesn't include inner boundary area) = 364.5 cm²
Area of the inner boundary = π r²
= 3.14 × 14 × 14
= 615.44 cm²
Total area of the ring (includes areas of both boundaries) = 615.44 + 364.5
= 979.94 cm²
Radius of the outer boundary = √(979.94/3.14)
=√312.08
Radius of the outer boundary is 17.66 cm.
-WonderGirl
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