A man travelled 2/11 of his journey by coach,17/22 by rail and walked the remaining 1 km .How far did he go?
Answers
Answer:
Man travveld total distace = 22 km
Step-by-step explanation:
Let the total distance travelled by a man (D) = X
∴Distance trvelled by coach Dc = (2/11) X
&
Distance travelled by Train Dt = (17/22) X
∴ Total distace traveled by train and coach
Dc + Dt = (2/11)X + (17/22) X
∴ Dc + Dt = (21/22)X
∴ Remaining distace of the total journey Dw = D - (Dc + Dt)
∴ Dw = X - (21/22)X
∴ Dw = (1/22) X .... (1)
But the remaining distance travelled is given as 1km by walk
∴ Dw = 1 .... (2)
From 1 & 2 we get
(1/22) X = 1
∴ X = 22 km
Man travveld total distace = 22 km
Answer:
22 km
Step-by-step explanation:
A man travelled 2/11 of his journey by coach,17/22 by rail and walked the remaining 1 km .How far did he go?
Let say total journey was J km
Travelled by coach = (2/11) J = 2J/11
Travelled by Rail = (17/22)J = 17J/22
By walk = 1 km
Total journey = J = 2J/11 + 17J/22 + 1
multiplying by 22
22J = 4J + 17J + 22
=> J = 22
total journey = 22 km