Question

A man travelled 2/5th journey by train, 1/3rd by bus and rest 3 kms on foot. Find the total distance of the journey.​

Answer 1

Step-by-step explanation:

Let total distance of journey be X km.

By train=2x/5 km

By bus=1x/3 km

Rest=3 km

ATQA,2x/5+1x/3+3=X

or 6x+5x+15/15=X

or 11x+15/15=X

or 11x+15=15x

or -4x=-15

or x=15/4=3.75

So by train=2×3.75/5=2×0.75=1.50 km

By bus=3.75/3=1.25 km

Answer 2

Answer:

Let the length of his total journey be x

So,

5

2

x+

3

1

x+

4

1

x+3=x

solving

x(

5

2

+

3

1

+

4

1

)−x=−3

=x(

5

2

+

3

1

+

4

1

−1)=−3

=x(

60

2×12+20+1×15−60

)=−3

=x(

60

24+20+15−60

)=−3

=x(

60

−1

)=−3

=

60

x

=3

∴x=180 km