Question

A man travelled one-third of a distance by bus ,two fifth by a taxi and the remaining 28km on scooter. how much distance did he travel

Answer 1

Here the answer...................

Answer 2

Hi...☺

Here is your answer...✌

LET the man travelled x km

GIVEN :

Travelled by bus = one-third of total distance

= (1/3)x = x/3

Travelled by taxi = two-fifth of total distance

= (2/5)x = 2x/5

Travelled by scooter = 28 km

Now,

Total distance travel = Travelled by Bus + Travelled by Taxi + Travelled by scooter


$x = \frac{ x}{3} + \frac{2x}{5} + 28\\ \\ x = \frac{5x + 6x}{15} + 28 \\ \\ x = \frac{11x}{15} + 28 \\ \\ x - \frac{11x}{15} = 28 \\ \\ \frac{15x - 11x}{15} = 28 \\ \\ 4x = 28 \times 15 \\ \\ x = \frac{28 \times 15}{4} \\ \\ x = 7 \times 15 \\ \\ x = 105 \: km$

HENCE,

The man did travelled 105 km