A man travelled two fifth of his journey by train , one third by bus , one fourth by car and remaining 3 km on foot. What is the length of his journey
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5
let the length of the journey be x
(2/5)x+(1/3)x+(1/4)x+3=x
x(2/5+1/3+1/4-1)+3=0
x(24+20+15-60)/60+3=0
x(-1/60)=-3
x=3*60=120 km
(2/5)x+(1/3)x+(1/4)x+3=x
x(2/5+1/3+1/4-1)+3=0
x(24+20+15-60)/60+3=0
x(-1/60)=-3
x=3*60=120 km
Answered by
0
Answer:
Let the whole distance he travelled be x km
Distance covered by train=1/5x
Distance covered by bus =1/3x
Distance covered by car=1/4x
distance covered on foot =3 km
1/3x+1/5x+1/4x+3=x
20+12+15/60x+3=x
x-42/60x =3
60x-42x/60=3
18/60x=3
x=3×60/18
x=180/18
x=10
therefore, length of his total journey =10 km
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