A man travelled two-fifth of his journey by train, one-third by bus, one-fourth by car and the remaining 3 km on foot. What is the length of his total journey
Answers
Answered by
14
let the total length of his journey be x km
given,
he travelled two-fifth of his journey by train
I.e., distance travelled by train is 2x/5 km
he travelled one-third by bus
I.e., distance travelled by bus is x/3 km
he travelled one-fourth by car
I.e., distance travelled by Cari's x/4 km
remaining 3 km on foot
therefore,2x/5+x/3+x/4+3=x
2x/5+x/3+x/4+3=x
(24x+20x+15x+180)/60=x
(59x+180)/60=x
59x+180=60x
60x-59x=180
x=180
therefore total length of his journey is 180km
given,
he travelled two-fifth of his journey by train
I.e., distance travelled by train is 2x/5 km
he travelled one-third by bus
I.e., distance travelled by bus is x/3 km
he travelled one-fourth by car
I.e., distance travelled by Cari's x/4 km
remaining 3 km on foot
therefore,2x/5+x/3+x/4+3=x
2x/5+x/3+x/4+3=x
(24x+20x+15x+180)/60=x
(59x+180)/60=x
59x+180=60x
60x-59x=180
x=180
therefore total length of his journey is 180km
Answered by
4
Answer:
Let the whole distance he travelled be x km
Distance covered by train=1/5x
Distance covered by bus =1/3x
Distance covered by car=1/4x
distance covered on foot =3 km
1/3x+1/5x+1/4x+3=x
20+12+15/60x+3=x
x-42/60x =3
60x-42x/60=3
18/60x=3
x=3×60/18
x=180/18
x=10
therefore, length of his total journey =10 km
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