A man travels 370 km partly by train and partly by car. If he covers 250 km by train and rest by car, he takes 18 minutes longer. Find the speed of train and that of car.
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Answered by
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Total Distance = 370 km
let speed of train= x km/h
speed of car = y km/h
Case 1 :
Distance travel by train = 250 km
Time taken to cover this distance = (250x) hour
Distance travel by car = 370-250 = 120 km
Time Taken to cover this distance = (120y) hour
Total time = 4 hours
So, 250x+120y=4
=> 250y+120x=4xy ............... (1)
Case 2 :
Distance travel by train = 130 km
Time taken to cover this distance = (130x) hour
Distance travel by car = 370-130 = 240 km
Time Taken to cover this distance = (240y) hour
Total time = 4 hours and 18 mintues = (4310) hours
So, 130x+240y=4310
=> 1300y+2400x=43xy ............... (2)
Multilply eq(1) by 20, we get
=> 5000y+2400x=80xy .......... (3)
Subtract (2) from (3), we get
=> 3700 y = 37xy
=> 37x = 3700
=> x = 100
Put value of x in eq(1). we get
=> 250y + 12000 = 400y
=> 12000 = 150y
=> y = 80
So Speed of train = 100 km/h
Speed of car = 80 km/h
let speed of train= x km/h
speed of car = y km/h
Case 1 :
Distance travel by train = 250 km
Time taken to cover this distance = (250x) hour
Distance travel by car = 370-250 = 120 km
Time Taken to cover this distance = (120y) hour
Total time = 4 hours
So, 250x+120y=4
=> 250y+120x=4xy ............... (1)
Case 2 :
Distance travel by train = 130 km
Time taken to cover this distance = (130x) hour
Distance travel by car = 370-130 = 240 km
Time Taken to cover this distance = (240y) hour
Total time = 4 hours and 18 mintues = (4310) hours
So, 130x+240y=4310
=> 1300y+2400x=43xy ............... (2)
Multilply eq(1) by 20, we get
=> 5000y+2400x=80xy .......... (3)
Subtract (2) from (3), we get
=> 3700 y = 37xy
=> 37x = 3700
=> x = 100
Put value of x in eq(1). we get
=> 250y + 12000 = 400y
=> 12000 = 150y
=> y = 80
So Speed of train = 100 km/h
Speed of car = 80 km/h
Answered by
0
Answer:
speed of car is 80km/hr
Step-by-step explanation:
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