the 5 th term of an arithmetic sequence is 38 and the 9,nt term is 66.what is its 25th term?
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heya here is ur Answer........
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sahilkumar1117p9zev6:
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Answered by
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given:
t5=38
t9=66
t25=?
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solution
t5=>a+4d=38.......1)
t9=>a+8d=66.......2)
From eq.1) and 2)
we have :»
=>4d=28
=>d=7
on putting value of d in eq.1) we have :
=>a+4d=38
=>a=10
now,
=>t25=a+24d
=>10+168
=>178
»»»»»»»»★««««««««
^_^
given:
t5=38
t9=66
t25=?
»»»»»»»»★««««««««
solution
t5=>a+4d=38.......1)
t9=>a+8d=66.......2)
From eq.1) and 2)
we have :»
=>4d=28
=>d=7
on putting value of d in eq.1) we have :
=>a+4d=38
=>a=10
now,
=>t25=a+24d
=>10+168
=>178
»»»»»»»»★««««««««
^_^
nice dear
Alle le u wlcm
^_^
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