Math, asked by SheroΔ, 1 year ago

a man Travels 370 km partly by train and partly by car. if he covers 250 km by train and the rest by car, it takes in 4 hours . but, if he travels 130 km by train and rest by car ,he takes 18 minutes longer .find the speed of the train and that of the car

Answers

Answered by Alia15
13

Let the speed of the car be C kmph
Let the speed of the train be T kmph

4 hours = 250 km / T kmph + (370 - 250) km / C kmph

          4 = 250/T + 120/C                          ---------------- equation 1

4 hrs 18 minutes = 130 km / T kmph + (370 - 130)km / C kmph

       258/60 = 4.3 = 130 / T + 240 / C      --------------- equation 2

 

Multiply equation 1 by 2 and subtract equation 2 from it.

       8 - 4.3 = 500/T - 130/T + 240/C - 240/C

       3.7 = 370 / T

       T = 370/3.7 = 100 kmph

Substitute the value of T in equation 1 to get,

 

       4 = 250/T + 120/C            ---------- equation 1

       4 = 250/100 + 120/C

       4 - 2.5 = 120/C

       C = 120/1.5 = 80 kmph

 

The train runs at 100 kmph and the car runs at 80 kmph

Answered by barish95644
11
the answer is for car 80kmph
and for train 100kmph
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