Question

A man travels 600km apart by train and partly by car. It takes 8 hours and 40 minutes if he travels 320 km by train and rest by car. It would take 30 minutes more if he travels 200 km by train and the rest by the car/. Find the speed of the train and by car separately.

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

Let speed of train be x

Let speed of care be y

We know that Distance = Speed * Time

ATQ :-

320/x + (600-320)/y = 8 + 40/60 hours = 8 + 2/3 hours..............................................(1)

200/x + (600-200)/y = 8 + 40/60 + 30/60 = 8 + 2/3 + 1/2...........................................(2)

I have just used the formula Time = Distance/Speed to write speed of train and car individually.

Writing (1) and (2) as linear equations by putting 1/x=a and 1/y=b..............................(3)

320a + 280b = 8 +2/3

200a + 400b = 8 + 2/3 + 1/2

Thus, solving the above equations, we get a = 1/80 and b=1/60

Now, x = 80 and y = 60 ................................................................................using (3)

So, speed of train is 80 kmph and speed of car is 60 kmph.

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Step-by-step explanation: