Question

a man Travels a distance of 4.5 metre towards east then 5 metre towards south and finally 1.5 metre towards east what is the total distance travelled and his resculant displacement​

Answer 1

QUESTION•

A man travels a distance of 1.5 m towards east then 2 m towards south and finally 4.5 m towards east. What is the total distance travelled and displacement?

Answer

Hint: The distance travelled by the man is the distance travelled along every direction. The displacement of the man is the position of its final point minus the position of its initial point. You can use Pythagoras theorem to determine the displacement.

Formula used:

Displacement of the body,

S=xf−xiS=xf−xi

Here, xfxf is the final distance and xixi is the initial distance.

Complete step by step answer:

We assume the man has started the journey from point A towards east and reached point B which is 1.5 m. Then he moved towards the south and reached point C which is 2 m. And then finally he travelled towards the east and reached at point D 4.5 m away from the point C. We can picture the journey of the man as shown in the figure below.

From the above figure, the total distance travelled by the man is,

d=AB+BC+CDd=AB+BC+CD

Substituting 1.5 m for AB, 2 m for BC and 4.5 m for CD in the above equation, we get,

d=1.5+2+4.5d=1.5+2+4.5

⇒d=8m⇒d=8m

Now, we know that the displacement is the difference between the final position and the initial position. Therefore, the displacement of the man is AD. From the above figure, we can express AD as,

AD2=AO2+OD2AD2=AO2+OD2

Or,

AD2=(AB+BO)2+BC2AD2=(AB+BO)2+BC2

Substituting 1.5 m for AB, 2 m for BC and 4.5 m for BO in the above equation, we get,

AD2=(1.5+4.5)2+22AD2=(1.5+4.5)2+22

⇒AD2=36+4⇒AD2=36+4

⇒AD2=40⇒AD2=40

⇒AD=40−−√⇒AD=40

∴AD=6.32m∴AD=6.32m

Therefore, the displacement of the man is 6.32 m.