Question

A man travels from a to b at a speed of 29 km in 29 minutes and he travel a distance from B to C with a speed of 39 km hour in 29 minute find that average speed of whole January

Answer 1

Answer:

29/29+39/29

=1+1.34

=2.34

now,

average speed=2.34/2

=1.75(approx)

Answer 2

Dear Student,

◆ Answer -

v = 34 km/hr

● Explanation -

# Given -

v1 = 29 km/hr

t1 = 29 min = 29/60 hr

v2 = 39 km/hr

t2 = 29 min = 29/60 hr

# Solution -

Total time of journey is given by -

t = t1 + t2

t = 29/60 + 29/60

t = 29/30 hr

Total distance of journey is -

d = d1 + d2

d = v1.t1 + v2.t2

d = 29×29/60 + 39×29/60

d = 14 + 18.85

d = 32.85 km

Average speed of the journey is -

v = d / t

v = 32.85 / (29/30)

v = 34 km/hr

Hence, average speed of whole journey is km.

Thanks dear. Hope this helps you...