a man twice as old as his ,20 years ago the age man was 12 times the age of the son find their present agesएक अस्पताल
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let age of man=2x
age of son=X
20 years ago age of father 2x-20
age of son= x-20
according to question 2x-20= 12(x-20)
= 2x-20=12x-240
=>10x=220
=>X= 22
so the age of father 2x = 44
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