Question

a man walk on straige road form it has house to
market 2.5 km away with speed of 5Km /hr
He written home with the speed of 7.5 km/hr.
from market to home find out avg speed
of the man over the intervel of 0 to 40 min.​

Answer 1

Answer:

He will take (2.5/5)=0.5hrs=30 min

Now he takes (2.5/7.5)= 1/3hrs= 20 min

so his total journey is of 50 min.

but we have to go only for 0 to 40 min

now from 0 to 30 min he travelled 2.5 km

in remaining 10 min he travelled 7.5/6= 1.25 km

total path travelled 3.75 km

therefore avg velocity = (3.75/40)*60 km/ hrs=5.625 km/ hrs

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