Math, asked by areeshakhan1234589, 1 month ago

A man walked 3km towards North, turned West and walked 2km, then turned North again and walked 1km and then turned East and walked 5km. How far is he from his starting point- (A) 4km (B) 7km (C) 5km (d)9km ​

Answers

Answered by harry366784
0

Answer:

5

Step-by-step explanation:

Let us consider a Cartesian plane thinking positive X-axis as South,

Negative x axis as North, Positive Y-axis as East and Negative as West.

A man walked along negative X-axis m and then parallel to negative Y-axis he walked m.

And then parallel to negative X-axis he walked m and finally walked m parallel to positive Y-axis and he has coordinates of .

He makes right angle triangle with base AC=4, side AB=3 and hypotenuse BC.

by Pythagoras theorem,

.

Hence from origin he is at distance of 5 m.

Thus, option A is the correct.

Answered by deepanshipal75
0

Step-by-step explanation:

option (c) 5cm hope this may help you

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